imagecreatefromjpeg

(PHP 4, PHP 5)

imagecreatefromjpeg — Create a new image from file or URL

Description

resource imagecreatefromjpeg ( string $filename )

imagecreatefromjpeg() returns an image identifier representing the image obtained from the given filename.

Tip

A URL can be used as a filename with this function if the fopen wrappers have been enabled. See fopen() for more details on how to specify the filename. See the Supported Protocols and Wrappers for links to information about what abilities the various wrappers have, notes on their usage, and information on any predefined variables they may provide.

Parameters

filename

Path to the JPEG image.

Return Values

Returns an image resource identifier on success, FALSE on errors.

Examples

Example #1 Example to handle an error during loading of a JPEG

<?php
function LoadJpeg($imgname)
{
    /* Attempt to open */
    $im = @imagecreatefromjpeg($imgname);

    /* See if it failed */
    if(!$im)
    {
        /* Create a black image */
        $im  = imagecreatetruecolor(150, 30);
        $bgc = imagecolorallocate($im, 255, 255, 255);
        $tc  = imagecolorallocate($im, 0, 0, 0);

        imagefilledrectangle($im, 0, 0, 150, 30, $bgc);

        /* Output an error message */
        imagestring($im, 1, 5, 5, 'Error loading ' . $imgname, $tc);
    }

    return $im;
}

header('Content-Type: image/jpeg');

$img = LoadJpeg('bogus.image');

imagejpeg($img);
imagedestroy($img);
?>

The above example will output something similar to:

Output of example : Example to handle an error during loading of a JPEG

Notes

Note: JPEG support is only available if PHP was compiled against GD-1.8 or later.

Warning

Windows versions of PHP prior to PHP 4.3.0 do not support access of remote files via this function, even if allow_url_fopen is enabled.